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Question Number 189977 by cherokeesay last updated on 25/Mar/23

	Answered by a.lgnaoui last updated on 26/Mar/23

	$t h e t o t a l e A r e a :$ $2 (12 \times 3, 5 + 9 \times 3, 5) = 147 m^{2}$ $A r e a o f w i n d o w s = 21 m^{2}$ $A r e a o f t i l e s = 147 - 21 = 126 m^{2} = 126 \times 10^{2} {c m}^{2}$ $A r e a o f o n e t i l e = 225 {c m}^{2} = 15 \times 10^{- 2} m^{2}$ $N u m b e r o f t i l e s n e c e s s a r y f o r t h e w a l l s :$ $= \frac{126}{15 \times 10^{- 2}} = 840 t i l e s$
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