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Question Number 190025 by Shrinava last updated on 26/Mar/23
Iff(x)=3x5+2x2Find:f(2−1)+f(1−2)+3
Answered by SEKRET last updated on 26/Mar/23
2−1=a1−2=−a3a5+2a2−3a5+2a2+3=4a2+3=4(2−1)2+3=4(3−22)+3=15−82
Commented by Shrinava last updated on 26/Mar/23
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