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Question Number 190027 by Shrinava last updated on 26/Mar/23
a2+b2=12ab=4Fund:a3+b3=?
Answered by SEKRET last updated on 26/Mar/23
+{a2+b2=122ab=8(a+b)2=20a+b=∓25a3+b3+3ab(a+b)=(∓25)3a3+b3=−12⋅(∓25)∓(25)3a3+b3=∓165
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