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Question Number 190038 by Shrinava last updated on 26/Mar/23

Find:   ((21 + (√(4a − 3)))/(4a + (√(3 − 4a))))

Find:21+4a34a+34a

Answered by Rasheed.Sindhi last updated on 26/Mar/23

Find:   ((21 + (√(4a − 3)))/(4a + (√(3 − 4a))))  Assuming the value is real  ⇒    4a−3≥0 ∧ 3−4a≥0  a≥(3/4) ∧ a≤(3/4)⇒a=(3/4)  • ((21 + (√(4a − 3)))/(4a + (√(3 − 4a))))=((21+0)/(4((3/4))+0))=7

Find:21+4a34a+34aAssumingthevalueisreal4a3034a0a34a34a=3421+4a34a+34a=21+04(34)+0=7

Commented by Shrinava last updated on 01/Apr/23

thank you professor cool

thankyouprofessorcool

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