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Question Number 190039 by Shrinava last updated on 26/Mar/23

$$\mathrm{b}+\sqrt{\mathrm{b}}-3=0$$ $$\mathrm{b}>0$$ $$\mathrm{find}{2\mathrm{b}}^2-14\mathrm{b}+28=?$$

Answered by cortano12 last updated on 26/Mar/23

$$\sqrt{\mathrm{b}}=3-\mathrm{b}\Rightarrow \mathrm{b}=9-6\mathrm{b}+{\mathrm{b}}^2$$ $$\Rightarrow {\mathrm{b}}^2-7\mathrm{b}+9=0$$ $$\Rightarrow {2\mathrm{b}}^2-14\mathrm{b}+18=0$$ $$\Rightarrow {2\mathrm{b}}^2-14\mathrm{b}+28=10$$

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