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Question Number 190082 by Rupesh123 last updated on 27/Mar/23

Answered by a.lgnaoui last updated on 29/Mar/23

L=(e^x^3 /x^3 )−((3(√((1−x)(1+x^2 +x))))/((x^3 −1)+1))+((√((1−x)(1+x)))/((x^2 −1)+1)) (e^x /x^3 )−((3(√(1−x)))/x^3 )+((√(1−x))/x^2 ) =(e^x^3 /x^3 )−[((3(√(1−x)))/x^3 )−x((√((1−x)))/x^3 ))] =(1/x^3 )(e^x^3 −((3(√(1−x)))/1)) x=(1/X) x→0 X→+∞ X^3 (e^(1/X^3 ) −3(√(1−(1/X))) ) lim_(X→∞) L=+∞(1−3)=−∞ β=−∞ 3!β=−∞

L=ex3x3−3(1−x)(1+x2+x)(x3−1)+1+(1−x)(1+x)(x2−1)+1exx3−31−xx3+1−xx2=ex3x3−[31−xx3−x(1−x)x3)]=1x3(ex3−31−x1)x=1Xx→0X→+∞X3(e1X3−31−1X)limX→∞L=+∞(1−3)=−∞β=−∞3!β=−∞

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