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Question Number 190137 by mustafazaheen last updated on 28/Mar/23
{fog−1(x)=3x+2gof(x)=2x−1findf(x)=?andfof(3)=?
Answered by 073 last updated on 28/Mar/23
f(x)=g−1(2x−1)g−1(x)=f(x+12)fof(x+12)=3x+2fof(x)=6x−1fof(3)=18−1=17fof(3)=17Mathlover
Answered by cortano12 last updated on 28/Mar/23
{(fog−1)(x)=3x+2(gof)(x)=2x−1⇒f(g−1(gof))(x)=3(2x−1)+2⇒f(f(x))=6x−1⇒f(f(3))=6.3−1=17
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