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Question Number 190165 by TUN last updated on 29/Mar/23

$$S_n=1+\frac{1}{2^2}+\frac{1}{3^2}+...+\frac{1}{n^2}$$ $$=>\underset{n\to \mathrm{\infty }}{\lim }{S}_n=¿$$

Answered by JDamian last updated on 29/Mar/23

$$\frac{{\pi }^2}{6}$$

Commented byTUN last updated on 10/Apr/23

$$howtosolveit$$

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