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Question Number 190172 by jlewis last updated on 29/Mar/23

$$Integrate$$$${\int }_0^1{Sin}^2\left(2\mathrm{\Pi }x\right)dx$$

Answered by mehdee42 last updated on 29/Mar/23

$$\frac{1}{2}{\int }_0^1(1-cos2\pi x)dx=\frac{1}{2}{(x-\frac{1}{2\pi }sin2\pi x)}_0^1=\frac{1}{2}$$

Commented by mr W last updated on 30/Mar/23

$${\sin }^2\left(2\pi x\right)=\frac{1-\cos \left(4\pi x\right)}{2}$$

Commented by mehdee42 last updated on 31/Mar/23

$$thanksforyou$$

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