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Question Number 190182 by SLVR last updated on 29/Mar/23

Lim_(x→π/2) ((sinx−sinx^(sinx) )/(1−sinx+logsinx))  a)4        b)2          c)1/2        d)none

Limxπ/2sinxsinxsinx1sinx+logsinxa)4b)2c)1/2d)none

Commented by SLVR last updated on 29/Mar/23

kindly help me

kindlyhelpme

Commented by SLVR last updated on 29/Mar/23

i tried but by LHospital Rule  its too lenghty..

itriedbutbyLHospitalRuleitstoolenghty..

Commented by Frix last updated on 29/Mar/23

Let sin x =t; t→1  Now l′Ho^� pital is possible ⇒ lim=2

Letsinx=t;t1NowlHopital^ispossiblelim=2

Commented by SLVR last updated on 29/Mar/23

Great....sir.Thanks

Great....sir.Thanks

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