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Question Number 190191 by normans last updated on 29/Mar/23

	Answered by a.lgnaoui last updated on 30/Mar/23

	$t h e A r e a d i v i d e d b y 4 p o r t i o n s$ $1 ∙ h e a d o f b i r d$ $A_{1} = \frac{1 \times π}{2}$ $2 ∙ t r o n c$ $A_{2} = \frac{2^{2} π}{2} - \frac{π}{2} = \frac{3 π}{2}$ $3 ∙ R i g h t W i n g (p o r t i o n)$ $A_{3} = 2 \times [\frac{π}{6} - \frac{1}{2} (\frac{1}{2} \times \frac{\sqrt{3}}{2})] = \frac{π}{3} - \frac{\sqrt{3}}{4}$ $A_{4} = 1 - \frac{π}{4}$ $t o t a l A r e a = \frac{π}{2} + \frac{3 π}{2} + \frac{π}{3} - \frac{π}{4} + \frac{4 - \sqrt{3}}{4}$ $= \frac{25 π + 12 - 3 \sqrt{3}}{12}$ $A r e a = 7, 112 {c m}^{2}$
	Commented by a.lgnaoui last updated on 30/Mar/23

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