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Question Number 190230 by 073 last updated on 29/Mar/23

	Answered by Rasheed.Sindhi last updated on 29/Mar/23

	$a_{5} = 5 - 1 = 4 [∵ 5 = 2 (2) + 1]$ $a_{6} = 2 (6) + 3 = 15 [∵ 6 = 2 (3)]$ $a_{5} + a_{6} = 4 + 15 = 19$
	Answered by a.lgnaoui last updated on 29/Mar/23

	$n = 5 \Rightarrow 5 i m p a i r (= 2 \times 2 + 1)$ $a_{5} = 5 - 1 = 4$ $n = 6 \Rightarrow 6 p a i r (6 = 2 \times 3)$ $a_{6} = 2 \times 6 + 3 = 15$ $a l o r s : a_{5} + a_{6} = 15 + 4$ $a_{5} + a_{6} = 19$
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