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Question Number 190325 by Shrinava last updated on 31/Mar/23

	Answered by mehdee42 last updated on 31/Mar/23

	$I = \int_{0}^{\frac{1}{2}} \frac{2 t a n \frac{β}{2} x}{α {t a n}^{2} \frac{β}{2} x + 2 t a n \frac{β}{2} x + α} d x$ $i f t a n \frac{β}{2} x = u \Rightarrow I = \int_{0}^{t a n \frac{β}{4}} \frac{4 d u}{α u^{2} + 2 u + α}$ $i t c a n b e s o l v e d$
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