solve for x ∈R (√(x−1))+(√(3x−5))+(√(4x−7))=4x−5


Question and Answers Forum

All Questions Topic List
Arithmetic Questions
Previous in All Question Next in All Question
Previous in Arithmetic Next in Arithmetic
Question Number 190339 by mr W last updated on 01/Apr/23

$s o l v e f o r x \in R$ $\sqrt{x - 1} + \sqrt{3 x - 5} + \sqrt{4 x - 7} = 4 x - 5$
	Answered by ajfour last updated on 01/Apr/23

	$\sqrt{x - 1} + \sqrt{3 x - 5} + \sqrt{4 x - 7}$ $= \frac{1}{2} (x - 1 + 3 x - 5 + 4 x - 7) + \frac{3}{2}$ $\Rightarrow {(p - 1)}^{2} + {(q - 1)}^{2} + {(r - 1)}^{2} = 0$ $p = \sqrt{x - 1} = q = \sqrt{3 x - 5} = r = \sqrt{4 x - 7} = 1$ $\Rightarrow x = 2, 3 x = 6, 4 x = 8$
	Commented by mehdee42 last updated on 01/Apr/23

	$v e r y n i c e$
	Commented by mr W last updated on 02/Apr/23


	Commented by ajfour last updated on 10/Apr/23
	https://youtu.be/0I8a9urBLB8
	Commented by ajfour last updated on 10/Apr/23

	$m y l a t e s t y o u t u b e v i d e o e x p l a i n i n g$ $h o w l o n g i t t a k e s t o e m p t y a w a t e r$ $f i l l e d t a n k, t h r o u g h a h o l e a t i t s$ $b o t t o m .$
Terms of Service
Privacy Policy
Contact: info@tinkutara.com

Question and Answers Forum