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Question Number 190392 by Shrinava last updated on 02/Apr/23

If a + b = 3 Find: ((a^2 + b^2 − 2a − 2b)/(a^2 − b^2 − 4a + 4))

Ifa+b=3Find:a2+b2−2a−2ba2−b2−4a+4

Commented by mokys last updated on 05/Apr/23

((a^2 +b^2 −2(a+b))/((a−b)(a+b)−4a+4)) = ((a^2 +(3−a)^2 −6)/(3(a−b)−4a+4)) = ((2a^2 +9−6a−6)/(3(2a−3)−4a+4))= ((2a^2 −6a+3)/(2a−5)) = ((2ab + 3)/(2(a−3)+1))= ((2ab+3)/(2b+1))

a2+b2−2(a+b)(a−b)(a+b)−4a+4=a2+(3−a)2−63(a−b)−4a+4=2a2+9−6a−63(2a−3)−4a+4=2a2−6a+32a−5=2ab+32(a−3)+1=2ab+32b+1

Answered by Frix last updated on 02/Apr/23

? b=3−a ((a^2 +b^2 −2a−2b)/(a^2 −b^2 −4a+4))=((2a^2 −6a+3)/(2a−5))

?b=3−aa2+b2−2a−2ba2−b2−4a+4=2a2−6a+32a−5

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