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Question Number 190522 by Rupesh123 last updated on 04/Apr/23

Answered by gatocomcirrose last updated on 05/Apr/23

$${\mathrm{g}}^{\prime }\left(\mathrm{y}\right)=\mathrm{f}\left(\mathrm{y}\right)\Rightarrow {\mathrm{g}}^{″}\left(\mathrm{y}\right)={\mathrm{f}}^{\prime }\left(\mathrm{y}\right)$$$${\mathrm{f}}^{\prime }\left(\mathrm{x}\right)=\mathrm{cosx}\sqrt{1+{\mathrm{sen}}^2\mathrm{x}}$$$${\mathrm{g}}^{″}\left(\pi /6\right)={\mathrm{f}}^{\prime }\left(\pi /6\right)=\frac{\sqrt{3}}{2}\sqrt{1+\frac{1}{4}}=\frac{\sqrt{15}}{4}$$

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