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Question Number 190760 by 073 last updated on 10/Apr/23

Answered by mehdee42 last updated on 10/Apr/23

$$\frac{1}{2{log}_{x}2}\times \frac{1}{{log}_{x}3}=\frac{1}{{log}_{x}2}+\frac{1}{2{log}_{x}3}$$$$\Rightarrow {lg}_{x}18=1\Rightarrow x=18$$

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