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Question Number 190781 by Tawa11 last updated on 11/Apr/23

Commented by mr W last updated on 11/Apr/23

$i f y o u u n d e r s t a n d t h e q u e s t i o n, t h e n$ $y o u s h o u l d b e a b l e t o s o l v e i t . i {d o n}^{'} t$ $u n d e r s t a n d t h e q u e s t i o n, s o i {c a n}^{'} t$ $s o l v e i t . i {d o n}^{'} t u n d e r s t a n d i t, b e c a u s e$ ${i t}^{'} s n o t c l e a r . a q u e s t i o n w h i c h i s$ $n o t u n i q u e l y c l e a r, i s a w r o n g q u e s t i o n .$
	Answered by ajfour last updated on 11/Apr/23

	$20 b o y s \equiv 3 m e n$ $s o 4 h o u r s \to 6 m e n$ $2 h o u r s \to 12 m e n$
	Commented by ajfour last updated on 11/Apr/23
	https://youtu.be/WGRDv1fYlh4 A mishap creating a projectile motion question
	Commented by Tawa11 last updated on 28/Apr/23

	$God bless you sir .$
	Answered by mr W last updated on 12/Apr/23

	$a s i h a v e s a i d t h e q u e s t i o n i s n o t c l e a r .$ $o n e p o s s i b l i t y i s :$ $3 m e n a n d 20 b o y s d o a j o b i n 4 h o u r s .$ $t h e m e n d o 20 / 3 t i m e s m u c h a s t h e$ $b o y s d o, t h a t m e a n s i f t h e 3 m e n d o x$ $j o b, t h e n t h e 20 b o y s d o \frac{3 x}{20} j o b .$ $x + \frac{3 x}{20} = 1 \Rightarrow x = \frac{20}{23}$ $t h a t m e a n s 3 m e n d o \frac{20}{23} j o b i n 4 h o u r s .$ $s a y e a c h m a n d o y j o b i n o n e h o u r,$ $t h e n y = \frac{20}{23 \times 3 \times 4} = \frac{5}{69} .$ $s o t o d o t h e j o b i n 2 h o u r s w e n e e d$ $\frac{1}{2 \times \frac{5}{69}} = 6.9 \approx 7 m e n .$
	Commented by Tawa11 last updated on 28/Apr/23

	$God bless you sir .$
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