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Question Number 190813 by Spillover last updated on 12/Apr/23

Answered by manxsol last updated on 12/Apr/23

Commented by manxsol last updated on 13/Apr/23

$$E=\frac{kq}{r^2}$$$$r^2=\frac{Q^2}{2}$$$$E_1=\frac{2kq}{Q^2}\frac{(-i,j)}{\sqrt{2}}$$$$E_2=\frac{2k\left(2q\right)}{Q^2}.\frac{(i,j)}{\sqrt{2}}$$$$E_3=\frac{2k\left(3q\right)}{Q^2}.\frac{(i,-j)}{\sqrt{2}}$$$$E_4=\frac{2k\left(4q\right)}{Q^2}.\frac{(-i,-j)}{\sqrt{2}}$$$$E_{resultante}=\frac{\sqrt{2}kq}{Q^2}[-i+j+2i+2j$$$$+3i-3j-4i-4j)$$$$E_{resul}=\frac{4\sqrt{2}kq}{Q^2}(-j)$$$$$$

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