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Question Number 190903 by Spillover last updated on 13/Apr/23

Answered by mr W last updated on 14/Apr/23

$$m_{P}a=m_{P}g\sin \alpha -T...\left(i\right)$$$$m_{Q}a=T-m_{Q}g\sin \beta ...\left(ii\right)$$$$\left(i\right):\left(ii\right):$$$$\frac{m_P}{m_Q}=\frac{m_{P}g\sin \alpha -T}{T-m_{Q}g\sin \beta }$$$$T=\frac{m_P{m}_Q(\sin \alpha +\sin \beta )g}{m_P+m_Q}$$$$T=\frac{0.65\times 0.65(\frac{63}{65}+\frac{16}{63})\times 10}{0.65+0.65}=3.95N✓$$

Commented by Spillover last updated on 14/Apr/23

$$nicesolution.thanks$$

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