Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 190982 by sciencestudentW last updated on 15/Apr/23

$$p\left(x\right)=2x^2{y}^3-3xy+10$$$$a_0=?a_1=?a_2=?a_{10}=?$$

Commented by mr W last updated on 16/Apr/23

$$whatdoyoumeanwith{a}_0,a_{1}etc?$$

Answered by a.lgnaoui last updated on 16/Apr/23

$$\mathrm{posons}{\mathrm{a}}_0=\mathrm{p}\left(0\right);{\mathrm{a}}_1=\mathrm{p}\left(1\right);{\mathrm{a}}_2=\mathrm{p}\left(2\right);{\mathrm{a}}_{10}=\mathrm{p}\left(10\right)$$$$\Rightarrow {\mathrm{a}}_0=10$$$${\mathrm{a}}_1=\mathrm{y}({2\mathrm{y}}^2-3)+10$$$${\mathrm{a}}_2=2\mathrm{y}({4\mathrm{y}}^2-3)+10$$$${\mathrm{a}}_{10}=10\mathrm{y}({20\mathrm{y}}^2-3)+10$$$$\mathrm{suite}$$$${\mathrm{a}}_1=\mathrm{y}({2\mathrm{y}}^2-3)+{\mathrm{a}}_0$$$${\mathrm{a}}_2=2[\mathrm{y}\left({2\mathrm{y}}^2\right)-3\mathrm{y}]+{\mathrm{a}}_0={2\mathrm{a}}_1-{\mathrm{a}}_0$$$${\mathrm{a}}_5={5\mathrm{a}}_1-{4\mathrm{a}}_0$$$$......$$$${\mathrm{a}}_{\mathrm{n}}={\mathrm{na}}_1-(\mathrm{n}-1){\mathrm{a}}_0=\mathrm{n}({\mathrm{a}}_1-1)+{\mathrm{a}}_0?$$$$$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com