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Question Number 191210 by TUN last updated on 20/Apr/23

2^x +2^(x+1) >3^x +3^(x+1)

2x+2x+1>3x+3x+1

Answered by ARUNG_Brandon_MBU last updated on 20/Apr/23

2^x +2^(x+1) >3^x +3^(x+1)   ⇒2^x (1+2)>3^x (1+3)  ⇒3.2^x >4.3^x  ⇒2^(x−2) >3^(x−1)   ⇒(x−2)ln2>(x−1)ln3  ⇒(ln2−ln3)x>2ln2−ln3  ⇒x < ((2ln2−ln3)/(ln2−ln3))      (∵ ln2−ln3 <0)

2x+2x+1>3x+3x+1 2x(1+2)>3x(1+3) 3.2x>4.3x2x2>3x1 (x2)ln2>(x1)ln3 (ln2ln3)x>2ln2ln3 x<2ln2ln3ln2ln3(ln2ln3<0)

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