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Question Number 191229 by mr W last updated on 21/Apr/23

evaluate  P_n =(a+sin θ)(a+sin (θ/2))(a+sin (θ/2^2 ))...(a+sin (θ/2^n ))

evaluate Pn=(a+sinθ)(a+sinθ2)(a+sinθ22)...(a+sinθ2n)

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