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Question Number 19134 by chernoaguero@gmail.com last updated on 05/Aug/17

If (1/((243)^x )) = (729)^y = 3^3 , then find the   value of  5x + 6y.

$$\mathrm{If}\:\frac{\mathrm{1}}{\left(\mathrm{243}\right)^{{x}} }\:=\:\left(\mathrm{729}\right)^{{y}} =\:\mathrm{3}^{\mathrm{3}} ,\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\: \\ $$$$\mathrm{value}\:\mathrm{of}\:\:\mathrm{5}{x}\:+\:\mathrm{6}{y}. \\ $$

Answered by Tinkutara last updated on 05/Aug/17

(1/3^(5x) ) = 3^3  ⇒ 5x = −3  3^(6y)  = 3^3  ⇒ 6y = 3  5x + 6y = 3 − 3 = 0

$$\frac{\mathrm{1}}{\mathrm{3}^{\mathrm{5}{x}} }\:=\:\mathrm{3}^{\mathrm{3}} \:\Rightarrow\:\mathrm{5}{x}\:=\:−\mathrm{3} \\ $$$$\mathrm{3}^{\mathrm{6}{y}} \:=\:\mathrm{3}^{\mathrm{3}} \:\Rightarrow\:\mathrm{6}{y}\:=\:\mathrm{3} \\ $$$$\mathrm{5}{x}\:+\:\mathrm{6}{y}\:=\:\mathrm{3}\:−\:\mathrm{3}\:=\:\mathrm{0} \\ $$

Commented by chernoaguero@gmail.com last updated on 05/Aug/17

thankx sir

$${thankx}\:{sir} \\ $$

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