Question and Answers Forum

All Questions      Topic List

Others Questions

Previous in All Question      Next in All Question      

Previous in Others      Next in Others      

Question Number 19137 by Tinkutara last updated on 05/Aug/17

Figure shows (x, t), (y, t) diagram of a particle moving in 2-dimensions. If the particle has a mass of 500 g, find the force (direction and magnitude) acting on the particle.

$$\mathrm{Figure}\:\mathrm{shows}\:\left({x},\:{t}\right),\:\left({y},\:{t}\right)\:\mathrm{diagram}\:\mathrm{of}\:\mathrm{a} \\ $$$$\mathrm{particle}\:\mathrm{moving}\:\mathrm{in}\:\mathrm{2}-\mathrm{dimensions}.\:\mathrm{If}\:\mathrm{the} \\ $$$$\mathrm{particle}\:\mathrm{has}\:\mathrm{a}\:\mathrm{mass}\:\mathrm{of}\:\mathrm{500}\:\mathrm{g},\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{force}\:\left(\mathrm{direction}\:\mathrm{and}\:\mathrm{magnitude}\right)\:\mathrm{acting} \\ $$$$\mathrm{on}\:\mathrm{the}\:\mathrm{particle}. \\ $$

Commented by Tinkutara last updated on 05/Aug/17

Answered by ajfour last updated on 05/Aug/17

a_x =0 y=u_y t+(1/2)a_y t^2 At t=1s 1=u_y +(1/2)a_y and at t=2s 4=2u_y +2a_y we thus obtain a_y =2m/s^2 , u_y =0 ⇒ a^→ =(2j^� )m/s^2 F^→ =ma^→ =((1/2)kg)(((2m)/s^2 ))j^� ⇒ F^→ =(j^� )N .

$$\mathrm{a}_{\mathrm{x}} =\mathrm{0} \\ $$$$\mathrm{y}=\mathrm{u}_{\mathrm{y}} \mathrm{t}+\frac{\mathrm{1}}{\mathrm{2}}\mathrm{a}_{\mathrm{y}} \mathrm{t}^{\mathrm{2}} \\ $$$$\mathrm{At}\:\:\mathrm{t}=\mathrm{1s} \\ $$$$\:\:\:\:\:\mathrm{1}=\mathrm{u}_{\mathrm{y}} +\frac{\mathrm{1}}{\mathrm{2}}\mathrm{a}_{\mathrm{y}} \:\:\mathrm{and}\:\mathrm{at}\:\:\mathrm{t}=\mathrm{2s}\:\: \\ $$$$\:\:\:\:\:\mathrm{4}=\mathrm{2u}_{\mathrm{y}} +\mathrm{2a}_{\mathrm{y}} \\ $$$$\mathrm{we}\:\mathrm{thus}\:\mathrm{obtain}\:\mathrm{a}_{\mathrm{y}} =\mathrm{2m}/\mathrm{s}^{\mathrm{2}} \:,\:\mathrm{u}_{\mathrm{y}} =\mathrm{0} \\ $$$$\Rightarrow\:\overset{\rightarrow} {\mathrm{a}}=\left(\mathrm{2}\hat {\mathrm{j}}\right)\mathrm{m}/\mathrm{s}^{\mathrm{2}} \\ $$$$\overset{\rightarrow} {\mathrm{F}}=\mathrm{m}\overset{\rightarrow} {\mathrm{a}}\:=\left(\frac{\mathrm{1}}{\mathrm{2}}\mathrm{kg}\right)\left(\frac{\mathrm{2m}}{\mathrm{s}^{\mathrm{2}} }\right)\hat {\mathrm{j}} \\ $$$$\:\Rightarrow\:\:\overset{\rightarrow} {\mathrm{F}}=\left(\hat {\mathrm{j}}\right)\mathrm{N}\:. \\ $$

Commented by ajfour last updated on 06/Aug/17

how do i know the degree of equation to the y−t graph. this is all that can be done.

$$\mathrm{how}\:\mathrm{do}\:\mathrm{i}\:\mathrm{know}\:\mathrm{the}\:\mathrm{degree}\:\mathrm{of} \\ $$$$\mathrm{equation}\:\mathrm{to}\:\mathrm{the}\:\mathrm{y}−\mathrm{t}\:\mathrm{graph}. \\ $$$$\mathrm{this}\:\mathrm{is}\:\mathrm{all}\:\mathrm{that}\:\mathrm{can}\:\mathrm{be}\:\mathrm{done}. \\ $$

Commented by Tinkutara last updated on 06/Aug/17

Thank you very much Sir!

$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{very}\:\mathrm{much}\:\mathrm{Sir}! \\ $$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com