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Question Number 191394 by Mingma last updated on 23/Apr/23

Answered by Rasheed.Sindhi last updated on 23/Apr/23

(√a) +((2022)/( (√b) ))=2023  2023(√b) −(√a) (√b) =2022  (√b) (2023−(√a) )=2×3×337   { (((√b) =2 ∧ 2023−(√a) =3×337)),(((√b) =3 ∧ 2023−(√a) =2×337)),(((√b)=337 ∧ 2023−(√a) =2×3 )),(((√b) =2×3 ∧ 2023−(√a) =337)),(((√b) =2×337 ∧ 2023−(√a) =3)),(((√b) =3×337 ∧ 2023−(√a) =2)),(((√b) =2×3×337 ∧ 2023−(√a) =1)) :}    { ((b =4 ∧ a =(2023−3×337)^2 )),((b =9 ∧ a =(2023−2×337)^2 )),((b=337^2  ∧ a =(2023−2×3)^2  )),((b =36 ∧ a =(2023−337)^2 )),((b =674^2  ∧ a =(2023−3)^2 )),((b =1011^2  ∧ a =(2023−2)^2 )),((b =2023^2  ∧ a =(2023−1)^2 )) :}

a+2022b=20232023bab=2022b(2023a)=2×3×337{b=22023a=3×337b=32023a=2×337b=3372023a=2×3b=2×32023a=337b=2×3372023a=3b=3×3372023a=2b=2×3×3372023a=1{b=4a=(20233×337)2b=9a=(20232×337)2b=3372a=(20232×3)2b=36a=(2023337)2b=6742a=(20233)2b=10112a=(20232)2b=20232a=(20231)2

Commented by Mingma last updated on 23/Apr/23

Very nice solution, sir!

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