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Question Number 191404 by Mingma last updated on 23/Apr/23

Answered by mr W last updated on 23/Apr/23

$$asQ191305but\theta =0°$$$$r=\frac{ab}{a+b+\sqrt{a^2+b^2}+(a+\sqrt{3}b)\sin \theta +(\sqrt{3}a+b)\cos \theta }$$$$with\theta =0°$$$$r=\frac{ab}{\sqrt{a^2+b^2}+(1+\sqrt{3})a+2b}$$$$witha=4,b=3:$$$$r=\frac{12}{15+4\sqrt{3}}\approx 0.547$$

Commented by mr W last updated on 23/Apr/23

Commented by Mingma last updated on 23/Apr/23

Excellent, sir!

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