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Question Number 191567 by leandrosriv02 last updated on 26/Apr/23

Answered by Frix last updated on 26/Apr/23

$$\int \frac{\sqrt{x}-1}{x^{\pi }}dx=\int x^{\frac{1}{2}-\pi }dx-\int x^{-\pi }dx$$$$\mathrm{Which}\mathrm{is}\mathrm{easy}\mathrm{to}\mathrm{solve}\mathrm{using}\int x^{r}dx=\frac{x^{r+1}}{r+1}$$$$\mathrm{but}\mathrm{within}[0,2]\mathrm{the}\mathrm{integral}\mathrm{does}\mathrm{not}$$$$\mathrm{converge}.$$

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