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Question Number 191579 by 073 last updated on 26/Apr/23

$$\mathrm{f}\left(\mathrm{x}\right)=\mid \mathrm{x}\mid$$$${\mathrm{f}}^{-1}\left(\mathrm{x}\right)=?$$$$\mathrm{solution}?$$

Answered by mr W last updated on 26/Apr/23

$$y=f\left(x\right)=\mid x\mid$$$$\Rightarrow x=\pm ywithy⩾0$$$$\Rightarrow f^{-1}\left(x\right)=\pm xwithx⩾0$$

Answered by mehdee42 last updated on 26/Apr/23

$$f,in\mathbb{R},isnot,onetoone.thereforeitisnotinvertable.$$

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