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Question Number 191582 by Matica last updated on 26/Apr/23
f(x)=xn.findA=f(1)+f′(1)1+f″(1)2+f‴(1)3+...+f(n)(1)n
Answered by aleks041103 last updated on 27/Apr/23
f(k)(x)=(xn)(k)={n!(n−k)!xn−k,k=0,1,...,n0,k>n⇒A=1+∑nk=1n!k(n−k)!
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