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Question Number 191595 by MATHEMATICSAM last updated on 26/Apr/23

a = ((xy)/(x + y)) , b = ((xz)/(x + z)) and c = ((yz)/(y + z)) .  Represent x in a, b, c form. [x, y, z ≠ 0]

a=xyx+y,b=xzx+zandc=yzy+z.Representxina,b,cform.[x,y,z0]

Answered by mehdee42 last updated on 26/Apr/23

(1/a)=(1/x)+(1/y)   (i) ,  (1/b)=(1/x)+(1/z)  (ii)  ,   (1/c)=(1/y)+(1/z)  (iii)  (i),(ii)⇒(1/a)+(1/b)=(2/x)+(1/y)+(1/z)⇒^((iii)) (1/a)+(1/b)=(2/x)+(1/c)  ⇒x=((ac+bc−ab)/(2abc))  ✓

1a=1x+1y(i),1b=1x+1z(ii),1c=1y+1z(iii)(i),(ii)1a+1b=2x+1y+1z(iii)1a+1b=2x+1cx=ac+bcab2abc

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