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Question Number 191735 by Spillover last updated on 29/Apr/23

Verify that   ┐(p→q)→(p∧^┐ q) is tautology using laws of  algebra

Verifythat(pq)(pq)istautologyusinglawsofalgebra

Answered by manxsol last updated on 30/Apr/23

∼(∼p q)→(p ∼q)  (∼p q) (p ∼q)  (∼p q) p} (∼p q ∼q)  {V  q} {V  q)  V V=V tautologia  p→q=∼p q  distributiva  p (q r)=p q) (p r)

(pq)(pq)(pq)(pq)(pq)p}(pqq){Vq}{Vq)VV=Vtautologiapq=∼pqdistributivap(qr)=pq)(pr)

Answered by aba last updated on 30/Apr/23

 determinant ((p,q,(⌉(p→q)),(p∧⌉q),(⌉(p→q)→(p∧⌉q))),(0,0,0,0,1),(0,1,0,0,1),(1,0,1,1,1),(1,1,0,0,1))

pq(pq)pq(pq)(pq)00001010011011111001

Commented by Spillover last updated on 30/Apr/23

read the question carefull.the question says  use the laws of algebra.Thanks for your solution

readthequestioncarefull.thequestionsaysusethelawsofalgebra.Thanksforyoursolution

Commented by aba last updated on 30/Apr/23

i know

iknow

Answered by Spillover last updated on 30/Apr/23

∼(p→q)→(p∧∼q)  ∼[(∼p∨q)∨∼(p∧∼q)    p∧∼q∨∼p∨q  p∨∼p∼q∨q  T∨T  T

(pq)(pq)[(pq)(pq)pqpqppqqTTT

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