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Question Number 191753 by Abdullahrussell last updated on 30/Apr/23
Answered by Frix last updated on 30/Apr/23
t3+pt2+qt+r=0s1=t12t2+t22t3+t32t1s2=t12t3+t22t1+t32t2⇒(s−s1)(s−s2)=s2+(pq−3r)s+p3q−6pqr+q3+9r2s1,2=3r−pq2±−4p3r+p2q2+18pqr−4q3−27r22Inthegivencasewegetthesolutions−3,24
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