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Question Number 191921 by Rupesh123 last updated on 03/May/23

Answered by deleteduser1 last updated on 03/May/23

$$\int (3x+5)dx=\frac{3x^2}{2}+5x+c$$$${\int }_{-4}^2(3x+5)dx=(16+c)-(4+c)=12$$$$\Rightarrow (4+{log}_{3}x)\left({log}_{3}x\right)=12$$$$\Rightarrow (4+p)p=12\Rightarrow p^2+4p-12=0(p={log}_{3}x)$$$$\Rightarrow p=-6or2$$$$\Rightarrow x=3^{-6}=\frac{1}{729}or9$$

Commented by Rupesh123 last updated on 04/May/23

Perfect ��

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