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Question Number 191950 by Shrinava last updated on 04/May/23

$$\sqrt{\mathrm{a}}=1+\frac{1}{\mathrm{a}}\mathrm{find}:{\mathrm{a}}^2-\mathrm{a}-\sqrt{\mathrm{a}}=?$$

Answered by deleteduser1 last updated on 04/May/23

$$\frac{1}{\sqrt{a}-1}=\frac{\sqrt{a}+1}{a-1}=a\Rightarrow a^2-a-\sqrt{a}=1$$

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