Question and Answers Forum

All Questions      Topic List

Geometry Questions

Previous in All Question      Next in All Question      

Previous in Geometry      Next in Geometry      

Question Number 191962 by ajfour last updated on 04/May/23

Answered by mr W last updated on 04/May/23

[(√((a+x)^2 −(a−x)^2 ))−(√((a+b)^2 −(a−b)^2 ))]^2 =(b+x)^2 −(2a−b−x)^2 [(√(ax))−(√(ab))]^2 =2a(x−a+b) x+2(√(bx))−2a+b=0 ⇒(√x)=−(√b)+(√(2a)) ⇒x=((√(2a))−(√b))^2 =2a+b−2(√(2ab))

[(a+x)2−(a−x)2−(a+b)2−(a−b)2]2=(b+x)2−(2a−b−x)2[ax−ab]2=2a(x−a+b)x+2bx−2a+b=0⇒x=−b+2a⇒x=(2a−b)2=2a+b−22ab

Commented by mr W last updated on 04/May/23

interesting!

interesting!

Commented by ajfour last updated on 05/May/23

(2(√(ax))−2(√(ab)))^2 =4a(x+b−a) ((√x)−(√b))^2 =x+b−a ⇒ a=2(√(bx))

(2ax−2ab)2=4a(x+b−a)(x−b)2=x+b−a⇒a=2bx

Terms of Service

Privacy Policy

Contact: info@tinkutara.com