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Question Number 192045 by Safiullah_21 last updated on 06/May/23

(1/((1+(√2))(1+(2)^(1/4) )(1+(2)^(1/8) )(1+(2)^(1/(16)) )))×(((1−(2)^(1/(16)) )/(1−(2_ )^(1/(16)) )))    ⇒_ ((1−(2)^(1/(16)) )/((1+(√2))(1+(2)^(1/4) )(1+(2)^(1/8) )(1−(2)^(1/8) )))⇒(1/((1+(√2))(1+(2)^(1/4) )(1−(2)^(1/4) )))

1(1+2)(1+24)(1+28)(1+216)×(12161216)1216(1+2)(1+24)(1+28)(128)1(1+2)(1+24)(124)

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