Question and Answers Forum

All Questions      Topic List

None Questions

Previous in All Question      Next in All Question      

Previous in None      Next in None      

Question Number 192049 by sciencestudentW last updated on 06/May/23

$$fog\left(x\right)=4x-1$$$$g\left(x\right)=x-2$$$$f\left(x\right)=?$$

Answered by deleteduser1 last updated on 06/May/23

$$f\left(g\left(x\right)\right)=4x-1\Rightarrow f(x-2)=4(x-2)+7$$$$\Rightarrow f\left(x\right)=4x+7$$

Answered by qaz last updated on 07/May/23

$$f\circ g=f\circ \left(\begin{array}{c}x\\ x-2\end{array}\right)=\left(\begin{array}{c}x\\ 4x-1\end{array}\right)$$$$\Rightarrow f=\left(\begin{array}{c}x\\ 4x-1\end{array}\right){\left(\begin{array}{c}x\\ x-2\end{array}\right)}^{-1}=\left(\begin{array}{c}x\\ 4x-1\end{array}\right)\left(\begin{array}{c}x-2\\ x\end{array}\right)=\left(\begin{array}{c}x-2\\ 4x-1\end{array}\right)=\left(\begin{array}{c}x\\ 4x+7\end{array}\right)$$$$\Rightarrow f\left(x\right)=4x+7$$

Terms of Service

Privacy Policy

Contact: info@tinkutara.com