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Question Number 192076 by sciencestudentW last updated on 07/May/23

$$f\left(x\right)=x^2+6x{f}^{-1}\left(x\right)=?$$

Answered by deleteduser1 last updated on 07/May/23

$$y=f\left(x\right)=x^2+6x={(x+3)}^2-9$$$$x=\underset{-}{+}\sqrt{y+9}-3$$$$\Rightarrow f^{-1}\left(x\right)=\underset{-}{+}\sqrt{x+9}-3$$

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