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Question Number 192098 by cortano12 last updated on 08/May/23

Answered by mehdee42 last updated on 08/May/23

$$\left(c\right)\frac{6}{7}✓$$

Commented by Skabetix last updated on 08/May/23

$$Howsir?$$$$Probabilitytheyarechosen:\frac{1}{7}\times \frac{1}{7}=\frac{1}{49}$$$$\Rightarrow ProbabilitytheyareNOTchosen:1-\frac{1}{49}$$$$=\frac{49}{49}-\frac{1}{49}=\frac{49-1}{49}=\frac{48}{49}\Rightarrow \left(e\right)$$

Commented by mehdee42 last updated on 08/May/23

$$groupsofmens:s,m_1,m_2,m_3,..,m_7$$$${women}^{\prime }sgroup:j,w_1,w_2,w_3,..,w_7$$$$n\left(S\right)=7!\mathrm{\&}n\left(A\right)=7!-6!=6\times 6!$$$$\Rightarrow p\left(A\right)=\frac{6}{7}$$

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