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Question Number 192173 by universe last updated on 10/May/23
provethat(x2+a2)4=(x4−6x2a2+a4)2+(4x3a−4xa3)2
Answered by mehdee42 last updated on 10/May/23
rightside=((x2−a2)2−4a2x2)2+16a2x2(x2−a2)2(x2−a2)4−8a2x2(x2−a2)2+16a2x2+16a2x2(x2−a2)2(x2−a2)4+8a2x2(x2−a2)2+16a2x2((x2−a2)2+4a2x2)2=(x2+a2)2✓
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