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Question Number 192203 by naka3546 last updated on 11/May/23

Answered by HeferH last updated on 11/May/23

$$(3\mathrm{h}-2\mathrm{x})2\mathrm{h}=3\mathrm{hx}$$$${6\mathrm{h}}^2-4\mathrm{hx}=3\mathrm{hx}$$$${6\mathrm{h}}^2=7\mathrm{hx}$$$$6\mathrm{h}=7\mathrm{x}$$$$\frac{6\mathrm{h}}{7}=\mathrm{x}$$$$\frac{\mathrm{ON}}{\mathrm{NB}}=\frac{3\mathrm{h}-\frac{6\mathrm{h}}{7}}{2\mathrm{h}+\frac{6\mathrm{h}}{7}}=\frac{\frac{21\mathrm{h}-6\mathrm{h}}{7}}{\frac{14\mathrm{h}+6\mathrm{h}}{7}}=\frac{15\mathrm{h}}{7}\cdot \frac{7}{20\mathrm{h}}=\frac{3}{4}$$

Commented by HeferH last updated on 11/May/23

Commented by naka3546 last updated on 12/May/23

$$\mathrm{Thank}\mathrm{you}$$

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