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Question Number 192227 by sonukgindia last updated on 12/May/23

Answered by senestro last updated on 12/May/23

$$...76$$

Commented by text last updated on 12/May/23

$$...76$$

Answered by JDamian last updated on 13/May/23

$$5+{(-1)}^n=\{\begin{array}{l}6\mathrm{\forall }n\in \left\{\stackrel{\cdot }{2}\right\}\subset \mathbb{N}\\ 4\mathrm{\forall }n\notin \left\{\stackrel{\cdot }{2}\right\}\subset \mathbb{N}\end{array}$$$$$$$$P=\underset{500\mathrm{pairs}}{\underbrace{\left(4\times 6\right)\times \left(4\times 6\right)\cdot \cdot \cdot \left(4\times 6\right)}}$$$$P={24}^{500}$$$${24}^n\mathrm{mod}100=\{\begin{array}{l}76\mathrm{\forall }n\in \left\{\stackrel{\cdot }{2}\right\}\subset \mathbb{N}\\ 24\mathrm{\forall }n\notin \left\{\stackrel{\cdot }{2}\right\}\subset \mathbb{N}\end{array}$$$$$$$${24}^{500}\mathrm{mod}100=76$$

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