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Question Number 192346 by Rupesh123 last updated on 15/May/23

Answered by som(math1967) last updated on 15/May/23

(((2cos30cos20+cos70+cos(180−70))/(cos20)))^8   =((((√3)cos20+cos 70−cos 70)/(cos20)))^8   =((((√3)cos20)/(cos20)))^8   =((√3))^8 =81

(2cos30cos20+cos70+cos(18070)cos20)8=(3cos20+cos70cos70cos20)8=(3cos20cos20)8=(3)8=81

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