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Question Number 192406 by josemate19 last updated on 17/May/23
∫x2−4xdx???
Answered by mehdee42 last updated on 17/May/23
x=2chu⇒dx=2shudu⇒I=2∫sh2uchudu=2∫(chu−1chu)du=2(shu−2tag−1eu)=x2−4−4tag−1(x+x2−42)+c✓
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