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Question Number 192440 by cortano12 last updated on 18/May/23

$$\mathrm{Given}\{\begin{array}{l}\mathrm{A}=\frac{{({\mathrm{p}}^2+{\mathrm{q}}^2+{\mathrm{r}}^2)}^2}{{\left(\mathrm{pq}\right)}^2+{\left(\mathrm{pr}\right)}^2+{\left(\mathrm{qr}\right)}^2}\\ \mathrm{B}=\frac{{\mathrm{q}}^2-\mathrm{pr}}{{\mathrm{p}}^2+{\mathrm{q}}^2+{\mathrm{r}}^2}\end{array}$$$$\mathrm{If}\mathrm{p}+\mathrm{q}+\mathrm{r}=0\mathrm{then}{\mathrm{A}}^2-4\mathrm{B}=?$$$$$$

Answered by Frix last updated on 18/May/23

$$r=-(p+q)\Rightarrow A=4\wedge B=\frac{1}{2}$$$$A^2-4B=14$$

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