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Question Number 192453 by Spillover last updated on 18/May/23

Find     lim_(n→∞)  ((1/n^2 )+(2/n^2 )+(3/n^2 )+...(n/n^2 ))

Findlimn(1n2+2n2+3n2+...nn2)

Answered by senestro last updated on 18/May/23

1/2

1/2

Answered by deleteduser1 last updated on 18/May/23

(1/n^2 )(((n(n+1))/2))=((n+1)/(2n))=(1/2)+(1/(2n))⇒lim_(n→∞) (Σ_(p=1 ) ^n (p/n^2 ))=(1/2)

1n2(n(n+1)2)=n+12n=12+12nlimn(np=1pn2)=12

Commented by Spillover last updated on 19/May/23

great.

great.

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