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Question Number 192543 by peter frank last updated on 20/May/23
Answered by leodera last updated on 20/May/23
Δ=∫0π2sin(x)sin(x)+cos(x)dxΔ=12∫0π2sin(x)+cos(x)sin(x)+cos(x)dx=12∫0π2dxΔ=π4
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