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Question Number 192550 by mokys last updated on 20/May/23

$$howcanfindthesum\underset{i=1}{\sum ^r}(2v_i+1)?$$

Answered by a.lgnaoui last updated on 20/May/23

$${\mathrm{S}}_{\mathrm{i}}=\sum _{\mathrm{i}=1}^{\mathrm{i}=\mathrm{r}}({2\mathrm{v}}_{\mathrm{i}}+1)=1+2\sum _{\mathrm{i}=1}^{\mathrm{i}=\mathrm{r}}{\mathrm{v}}_{\mathrm{i}}$$$$=1+2({\mathrm{v}}_1+{\mathrm{v}}_2+{\mathrm{v}}_3+....{\mathrm{v}}_{\mathrm{r}})$$

Commented by JDamian last updated on 20/May/23

$$wrong$$$$=\mathit{r}+2({\mathrm{v}}_1+{\mathrm{v}}_2+{\mathrm{v}}_3+....{\mathrm{v}}_{\mathrm{r}})$$

Commented by a.lgnaoui last updated on 20/May/23

$$2\sum _{\mathrm{i}=1}^{\mathrm{i}=\mathrm{r}}{\mathrm{v}}_{\mathrm{i}}+(1+1+1+...+1)\left(1\times \mathrm{r}\right)$$$$=\mathrm{r}+2\sum _{\mathrm{i}=1}^{\mathrm{i}=\mathrm{r}}{\mathrm{v}}_{\mathrm{i}}$$$$\mathrm{thanks}\mathrm{for}\mathrm{help}$$

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