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Question Number 192570 by mechanics last updated on 21/May/23

Answered by cortano12 last updated on 21/May/23

$$\mid {\mathrm{x}}^2-4\mid <5$$$$({\mathrm{x}}^2-9)({\mathrm{x}}^2+1)<0$$$$(\mathrm{x}+3)(\mathrm{x}-3)({\mathrm{x}}^2+1)<0$$$$\therefore -3<\mathrm{x}<3$$

Answered by Skabetix last updated on 21/May/23

$$\mid x\mid +\mid x+2\mid +\mid 2-x\mid ⩽8\Rightarrow -\frac{8}{3}⩽x⩽\frac{8}{3}$$

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